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x\left(2x^{2}+3x-2\right)
Factor out x.
a+b=3 ab=2\left(-2\right)=-4
Consider 2x^{2}+3x-2. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx-2. To find a and b, set up a system to be solved.
-1,4 -2,2
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -4.
-1+4=3 -2+2=0
Calculate the sum for each pair.
a=-1 b=4
The solution is the pair that gives sum 3.
\left(2x^{2}-x\right)+\left(4x-2\right)
Rewrite 2x^{2}+3x-2 as \left(2x^{2}-x\right)+\left(4x-2\right).
x\left(2x-1\right)+2\left(2x-1\right)
Factor out x in the first and 2 in the second group.
\left(2x-1\right)\left(x+2\right)
Factor out common term 2x-1 by using distributive property.
x\left(2x-1\right)\left(x+2\right)
Rewrite the complete factored expression.