Solve 2x^3+0,4x^2-[0,4bx-3/4x^2+(-5bx+0,4x^3)-2/5bx]

$$2 x ^ { 3 } + 0,4 x ^ { 2 } - [ 0,4 b x - \frac { 3 } { 4 } x ^ { 2 } + ( - 5 b x + 0,4 x ^ { 3 } ) - \frac { 2 } { 5 } b x ]$$

Evaluate

$$\frac{8x^{3}}{5}+5bx+\frac{23x^{2}}{20}$$

Solution Steps

Combine 0,4bx and -5bx to get -4,6bx.

$$2x^{3}+0,4x^{2}-\left(-4,6bx-\frac{3}{4}x^{2}+0,4x^{3}-\frac{2}{5}bx\right)$$

Combine -4,6bx and -\frac{2}{5}bx to get -5bx.

$$2x^{3}+0,4x^{2}-\left(-5bx-\frac{3}{4}x^{2}+0,4x^{3}\right)$$

To find the opposite of -5bx-\frac{3}{4}x^{2}+0,4x^{3}, find the opposite of each term.

$$2x^{3}+0,4x^{2}+5bx+\frac{3}{4}x^{2}-0,4x^{3}$$

Combine 0,4x^{2} and \frac{3}{4}x^{2} to get \frac{23}{20}x^{2}.

$$2x^{3}+\frac{23}{20}x^{2}+5bx-0,4x^{3}$$

Combine 2x^{3} and -0,4x^{3} to get 1,6x^{3}.

$$1,6x^{3}+\frac{23}{20}x^{2}+5bx$$

Expand

$$\frac{8x^{3}}{5}+5bx+\frac{23x^{2}}{20}$$

Solution Steps

Combine 0,4bx and -5bx to get -4,6bx.

$$2x^{3}+0,4x^{2}-\left(-4,6bx-\frac{3}{4}x^{2}+0,4x^{3}-\frac{2}{5}bx\right)$$

Combine -4,6bx and -\frac{2}{5}bx to get -5bx.

$$2x^{3}+0,4x^{2}-\left(-5bx-\frac{3}{4}x^{2}+0,4x^{3}\right)$$

To find the opposite of -5bx-\frac{3}{4}x^{2}+0,4x^{3}, find the opposite of each term.

$$2x^{3}+0,4x^{2}+5bx+\frac{3}{4}x^{2}-0,4x^{3}$$

Combine 0,4x^{2} and \frac{3}{4}x^{2} to get \frac{23}{20}x^{2}.

$$2x^{3}+\frac{23}{20}x^{2}+5bx-0,4x^{3}$$

Combine 2x^{3} and -0,4x^{3} to get 1,6x^{3}.

$$1,6x^{3}+\frac{23}{20}x^{2}+5bx$$