Solve 2x^2-5y=0

$$2 x ^ { 2 } - 5 y = 0$$

Solve for y

$$y=\frac{2x^{2}}{5}$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-5y=-2x^{2}$$

Divide both sides by -5.

$$\frac{-5y}{-5}=-\frac{2x^{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=-\frac{2x^{2}}{-5}$$

Divide -2x^{2} by -5.

$$y=\frac{2x^{2}}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{10y}}{2}$$

$$x=\frac{\sqrt{10y}}{2}$$

Solve for x

$$x=\frac{\sqrt{10y}}{2}$$

$$x=-\frac{\sqrt{10y}}{2}\text{, }y\geq 0$$