Solve 2x^2-4x+m=0

$$2 x ^ { 2 } - 4 x + m = 0$$

Solve for m

$$m=-2x\left(x-2\right)$$

Solution Steps

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x+m=-2x^{2}$$

Add 4x to both sides.

$$m=-2x^{2}+4x$$

Solve for x (complex solution)

$$x=\frac{\sqrt{4-2m}}{2}+1$$

$$x=-\frac{\sqrt{4-2m}}{2}+1$$

Solve for x

$$x=\frac{\sqrt{4-2m}}{2}+1$$

$$x=-\frac{\sqrt{4-2m}}{2}+1\text{, }m\leq 2$$