2 x ^ { 2 } - 28 x + 80 = 2 ( x ^ { 2 }
Solve for x
x = \frac{20}{7} = 2\frac{6}{7} \approx 2.857142857
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2x^{2}-28x+80-2x^{2}=0
Subtract 2x^{2} from both sides.
-28x+80=0
Combine 2x^{2} and -2x^{2} to get 0.
-28x=-80
Subtract 80 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-80}{-28}
Divide both sides by -28.
x=\frac{20}{7}
Reduce the fraction \frac{-80}{-28} to lowest terms by extracting and canceling out -4.
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