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2x^{2}-164x+480=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-164\right)±\sqrt{\left(-164\right)^{2}-4\times 2\times 480}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -164 for b, and 480 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-164\right)±\sqrt{26896-4\times 2\times 480}}{2\times 2}
Square -164.
x=\frac{-\left(-164\right)±\sqrt{26896-8\times 480}}{2\times 2}
Multiply -4 times 2.
x=\frac{-\left(-164\right)±\sqrt{26896-3840}}{2\times 2}
Multiply -8 times 480.
x=\frac{-\left(-164\right)±\sqrt{23056}}{2\times 2}
Add 26896 to -3840.
x=\frac{-\left(-164\right)±4\sqrt{1441}}{2\times 2}
Take the square root of 23056.
x=\frac{164±4\sqrt{1441}}{2\times 2}
The opposite of -164 is 164.
x=\frac{164±4\sqrt{1441}}{4}
Multiply 2 times 2.
x=\frac{4\sqrt{1441}+164}{4}
Now solve the equation x=\frac{164±4\sqrt{1441}}{4} when ± is plus. Add 164 to 4\sqrt{1441}.
x=\sqrt{1441}+41
Divide 164+4\sqrt{1441} by 4.
x=\frac{164-4\sqrt{1441}}{4}
Now solve the equation x=\frac{164±4\sqrt{1441}}{4} when ± is minus. Subtract 4\sqrt{1441} from 164.
x=41-\sqrt{1441}
Divide 164-4\sqrt{1441} by 4.
x=\sqrt{1441}+41 x=41-\sqrt{1441}
The equation is now solved.
2x^{2}-164x+480=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
2x^{2}-164x+480-480=-480
Subtract 480 from both sides of the equation.
2x^{2}-164x=-480
Subtracting 480 from itself leaves 0.
\frac{2x^{2}-164x}{2}=-\frac{480}{2}
Divide both sides by 2.
x^{2}+\left(-\frac{164}{2}\right)x=-\frac{480}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}-82x=-\frac{480}{2}
Divide -164 by 2.
x^{2}-82x=-240
Divide -480 by 2.
x^{2}-82x+\left(-41\right)^{2}=-240+\left(-41\right)^{2}
Divide -82, the coefficient of the x term, by 2 to get -41. Then add the square of -41 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-82x+1681=-240+1681
Square -41.
x^{2}-82x+1681=1441
Add -240 to 1681.
\left(x-41\right)^{2}=1441
Factor x^{2}-82x+1681. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-41\right)^{2}}=\sqrt{1441}
Take the square root of both sides of the equation.
x-41=\sqrt{1441} x-41=-\sqrt{1441}
Simplify.
x=\sqrt{1441}+41 x=41-\sqrt{1441}
Add 41 to both sides of the equation.
x ^ 2 -82x +240 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 2
r + s = 82 rs = 240
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 41 - u s = 41 + u
Two numbers r and s sum up to 82 exactly when the average of the two numbers is \frac{1}{2}*82 = 41. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(41 - u) (41 + u) = 240
To solve for unknown quantity u, substitute these in the product equation rs = 240
1681 - u^2 = 240
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 240-1681 = -1441
Simplify the expression by subtracting 1681 on both sides
u^2 = 1441 u = \pm\sqrt{1441} = \pm \sqrt{1441}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =41 - \sqrt{1441} = 3.039 s = 41 + \sqrt{1441} = 78.961
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.