Solve 2x^2*2^2y=1

$$2 x ^ { 2 } \times 2 ^ { 2 } y = 1$$

Solve for y

$$y=\frac{1}{8x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2^{3}x^{2}y=1$$

Calculate 2 to the power of 3 and get 8.

$$8x^{2}y=1$$

Divide both sides by 8x^{2}.

$$\frac{8x^{2}y}{8x^{2}}=\frac{1}{8x^{2}}$$

Dividing by 8x^{2} undoes the multiplication by 8x^{2}.

$$y=\frac{1}{8x^{2}}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{2}y^{-\frac{1}{2}}}{4}$$

$$x=\frac{\sqrt{2}y^{-\frac{1}{2}}}{4}\text{, }y\neq 0$$

Solve for x

$$x=\frac{\sqrt{\frac{2}{y}}}{4}$$

$$x=-\frac{\sqrt{\frac{2}{y}}}{4}\text{, }y>0$$