Solve 2x^2=-5y+3

$$2 x ^ { 2 } = - 5 y + 3$$

Solve for y

$$y=\frac{3-2x^{2}}{5}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-5y+3=2x^{2}$$

Subtract 3 from both sides.

$$-5y=2x^{2}-3$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{2x^{2}-3}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{2x^{2}-3}{-5}$$

Divide 2x^{2}-3 by -5.

$$y=\frac{3-2x^{2}}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{6-10y}}{2}$$

$$x=\frac{\sqrt{6-10y}}{2}$$

Solve for x

$$x=\frac{\sqrt{6-10y}}{2}$$

$$x=-\frac{\sqrt{6-10y}}{2}\text{, }y\leq \frac{3}{5}$$