Solve 2x^2+m-4=0

$$2 x ^ { 2 } + m - 4 = 0$$

Solve for m

$$m=4-2x^{2}$$

Solution Steps

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$m-4=-2x^{2}$$

Add 4 to both sides.

$$m=-2x^{2}+4$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{8-2m}}{2}$$

$$x=\frac{\sqrt{8-2m}}{2}$$

Solve for x

$$x=\frac{\sqrt{8-2m}}{2}$$

$$x=-\frac{\sqrt{8-2m}}{2}\text{, }m\leq 4$$