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x\left(2x+84\right)=0
Factor out x.
x=0 x=-42
To find equation solutions, solve x=0 and 2x+84=0.
2x^{2}+84x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-84±\sqrt{84^{2}}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 84 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-84±84}{2\times 2}
Take the square root of 84^{2}.
x=\frac{-84±84}{4}
Multiply 2 times 2.
x=\frac{0}{4}
Now solve the equation x=\frac{-84±84}{4} when ± is plus. Add -84 to 84.
x=0
Divide 0 by 4.
x=-\frac{168}{4}
Now solve the equation x=\frac{-84±84}{4} when ± is minus. Subtract 84 from -84.
x=-42
Divide -168 by 4.
x=0 x=-42
The equation is now solved.
2x^{2}+84x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{2x^{2}+84x}{2}=\frac{0}{2}
Divide both sides by 2.
x^{2}+\frac{84}{2}x=\frac{0}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}+42x=\frac{0}{2}
Divide 84 by 2.
x^{2}+42x=0
Divide 0 by 2.
x^{2}+42x+21^{2}=21^{2}
Divide 42, the coefficient of the x term, by 2 to get 21. Then add the square of 21 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+42x+441=441
Square 21.
\left(x+21\right)^{2}=441
Factor x^{2}+42x+441. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+21\right)^{2}}=\sqrt{441}
Take the square root of both sides of the equation.
x+21=21 x+21=-21
Simplify.
x=0 x=-42
Subtract 21 from both sides of the equation.