Solve for y
y=-\frac{x^{2}}{2}+\frac{3z}{4}
Solve for x
x=\frac{\sqrt{6z-8y}}{2}
x=-\frac{\sqrt{6z-8y}}{2}\text{, }y\leq \frac{3z}{4}
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4y=3z-2x^{2}
Subtract 2x^{2} from both sides.
\frac{4y}{4}=\frac{3z-2x^{2}}{4}
Divide both sides by 4.
y=\frac{3z-2x^{2}}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{x^{2}}{2}+\frac{3z}{4}
Divide 3z-2x^{2} by 4.
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