Solve 2x^2+3z=5

$$2 x ^ { 2 } + 3 z = 5$$

Solve for z

$$z=\frac{5-2x^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides.

$$3z=5-2x^{2}$$

Divide both sides by 3.

$$\frac{3z}{3}=\frac{5-2x^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$z=\frac{5-2x^{2}}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{10-6z}}{2}$$

$$x=\frac{\sqrt{10-6z}}{2}$$

Solve for x

$$x=\frac{\sqrt{10-6z}}{2}$$

$$x=-\frac{\sqrt{10-6z}}{2}\text{, }z\leq \frac{5}{3}$$