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Solve for y
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Solve for x (complex solution)
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3y+4=-2x^{2}
Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.
3y=-2x^{2}-4
Subtract 4 from both sides.
\frac{3y}{3}=\frac{-2x^{2}-4}{3}
Divide both sides by 3.
y=\frac{-2x^{2}-4}{3}
Dividing by 3 undoes the multiplication by 3.