Solve 2x^2+20x-14-y=0

$$2 x ^ { 2 } + 20 x - 14 - y = 0$$

Solve for y

$$y=2\left(x^{2}+10x-7\right)$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$20x-14-y=-2x^{2}$$

Subtract 20x from both sides.

$$-14-y=-2x^{2}-20x$$

Add 14 to both sides.

$$-y=-2x^{2}-20x+14$$

The equation is in standard form.

$$-y=14-20x-2x^{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{14-20x-2x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{14-20x-2x^{2}}{-1}$$

Divide -2x^{2}-20x+14 by -1.

$$y=2x^{2}+20x-14$$

Solve for x (complex solution)

$$x=\frac{\sqrt{2y+128}}{2}-5$$

$$x=-\frac{\sqrt{2y+128}}{2}-5$$

Solve for x

$$x=\frac{\sqrt{2y+128}}{2}-5$$

$$x=-\frac{\sqrt{2y+128}}{2}-5\text{, }y\geq -64$$