Solve 2x^2+(-16+y)x+5y-210=0

$$2 x ^ { 2 } + ( - 16 + y ) x + 5 y - 210 = 0$$

Solve for y

$$y=-\frac{2\left(x-15\right)\left(x+7\right)}{x+5}$$

$$x\neq -5$$

Steps for Solving Linear Equation

Use the distributive property to multiply -16+y by x.

$$2x^{2}-16x+yx+5y-210=0$$

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-16x+yx+5y-210=-2x^{2}$$

Add 16x to both sides.

$$yx+5y-210=-2x^{2}+16x$$

Add 210 to both sides.

$$yx+5y=-2x^{2}+16x+210$$

Combine all terms containing y.

$$\left(x+5\right)y=-2x^{2}+16x+210$$

The equation is in standard form.

$$\left(x+5\right)y=210+16x-2x^{2}$$

Divide both sides by x+5.

$$\frac{\left(x+5\right)y}{x+5}=-\frac{2\left(x-15\right)\left(x+7\right)}{x+5}$$

Dividing by x+5 undoes the multiplication by x+5.

$$y=-\frac{2\left(x-15\right)\left(x+7\right)}{x+5}$$

Solve for x

$$x=\frac{\sqrt{y^{2}-72y+1936}}{4}-\frac{y}{4}+4$$

$$x=-\frac{\sqrt{y^{2}-72y+1936}}{4}-\frac{y}{4}+4$$