Solve 2x^2+cosx-a=0

$$2 x ^ { 2 } + \cos x - a = 0$$

Solve for a

$$a=\cos(x)+2x^{2}$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$\cos(x)-a=-2x^{2}$$

Subtract \cos(x) from both sides.

$$-a=-2x^{2}-\cos(x)$$

The equation is in standard form.

$$-a=-\cos(x)-2x^{2}$$

Divide both sides by -1.

$$\frac{-a}{-1}=\frac{-\cos(x)-2x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$a=\frac{-\cos(x)-2x^{2}}{-1}$$

Divide -2x^{2}-\cos(x) by -1.

$$a=\cos(x)+2x^{2}$$