Solve for x
x=\frac{7-3y}{2}
Solve for y
y=\frac{7-2x}{3}
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2x=7-3y
The equation is in standard form.
\frac{2x}{2}=\frac{7-3y}{2}
Divide both sides by 2.
x=\frac{7-3y}{2}
Dividing by 2 undoes the multiplication by 2.
7-3y=2x
Swap sides so that all variable terms are on the left hand side.
-3y=2x-7
Subtract 7 from both sides.
\frac{-3y}{-3}=\frac{2x-7}{-3}
Divide both sides by -3.
y=\frac{2x-7}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7-2x}{3}
Divide 2x-7 by -3.
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