Solve 2x=4y^2+4

$$2 x = 4 y ^ { 2 } + 4$$

Solve for x

$$x=2\left(y^{2}+1\right)$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2x=4y^{2}+4$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{4y^{2}+4}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{4y^{2}+4}{2}$$

Divide 4y^{2}+4 by 2.

$$x=2y^{2}+2$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{2\left(x-2\right)}}{2}$$

$$y=\frac{\sqrt{2\left(x-2\right)}}{2}$$

Solve for y

$$y=\frac{\sqrt{2\left(x-2\right)}}{2}$$

$$y=-\frac{\sqrt{2\left(x-2\right)}}{2}\text{, }x\geq 2$$