Solve for x
x=\frac{-3y-3}{2}
Solve for y
y=-\frac{2x}{3}-1
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2x=-3y-3
The equation is in standard form.
\frac{2x}{2}=\frac{-3y-3}{2}
Divide both sides by 2.
x=\frac{-3y-3}{2}
Dividing by 2 undoes the multiplication by 2.
-3-3y=2x
Swap sides so that all variable terms are on the left hand side.
-3y=2x+3
Add 3 to both sides.
\frac{-3y}{-3}=\frac{2x+3}{-3}
Divide both sides by -3.
y=\frac{2x+3}{-3}
Dividing by -3 undoes the multiplication by -3.
y=-\frac{2x}{3}-1
Divide 2x+3 by -3.
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