Solve 2x=(a+b)*z

$$2 x = ( a + b ) \times z$$

Solve for a

$$\left\{\begin{matrix}a=-b+\frac{2x}{z}\text{, }&z\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply a+b by z.

$$2x=az+bz$$

Swap sides so that all variable terms are on the left hand side.

$$az+bz=2x$$

Subtract bz from both sides.

$$az=2x-bz$$

The equation is in standard form.

$$za=2x-bz$$

Divide both sides by z.

$$\frac{za}{z}=\frac{2x-bz}{z}$$

Dividing by z undoes the multiplication by z.

$$a=\frac{2x-bz}{z}$$

Divide 2x-bz by z.

$$a=-b+\frac{2x}{z}$$

Solve for b

$$\left\{\begin{matrix}b=-a+\frac{2x}{z}\text{, }&z\neq 0\\b\in \mathrm{R}\text{, }&x=0\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply a+b by z.

$$2x=az+bz$$

Swap sides so that all variable terms are on the left hand side.

$$az+bz=2x$$

Subtract az from both sides.

$$bz=2x-az$$

The equation is in standard form.

$$zb=2x-az$$

Divide both sides by z.

$$\frac{zb}{z}=\frac{2x-az}{z}$$

Dividing by z undoes the multiplication by z.

$$b=\frac{2x-az}{z}$$

Divide 2x-az by z.

$$b=-a+\frac{2x}{z}$$