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2x=\frac{3\sqrt{6}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{3\sqrt{6}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
2x=\frac{3\sqrt{6}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
2x=\frac{3\sqrt{3}\sqrt{2}\sqrt{3}}{3}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
2x=\frac{3\times 3\sqrt{2}}{3}
Multiply \sqrt{3} and \sqrt{3} to get 3.
2x=3\sqrt{2}
Cancel out 3 and 3.
\frac{2x}{2}=\frac{3\sqrt{2}}{2}
Divide both sides by 2.
x=\frac{3\sqrt{2}}{2}
Dividing by 2 undoes the multiplication by 2.