Solve for x
x<\frac{1}{3}
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2x+10x<4
Add 10x to both sides.
12x<4
Combine 2x and 10x to get 12x.
x<\frac{4}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x<\frac{1}{3}
Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.
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