Solve 2x+y48+5*4/8*1,23+10/83

$$2 x + y 48 + 5 \cdot \frac { 4 } { 8 } \cdot 1,23 + \frac { 10 } { 83 }$$

Evaluate

$$2x+y_{48}+\frac{10609}{3320}$$

Solution Steps

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$2x+y_{48}+5\times \frac{1}{2}\times 1,23+\frac{10}{83}$$

Multiply 5 and \frac{1}{2} to get \frac{5}{2}.

$$2x+y_{48}+\frac{5}{2}\times 1,23+\frac{10}{83}$$

Convert decimal number 1,23 to fraction \frac{123}{100}.

$$2x+y_{48}+\frac{5}{2}\times \frac{123}{100}+\frac{10}{83}$$

Multiply \frac{5}{2} times \frac{123}{100} by multiplying numerator times numerator and denominator times denominator.

$$2x+y_{48}+\frac{5\times 123}{2\times 100}+\frac{10}{83}$$

Do the multiplications in the fraction \frac{5\times 123}{2\times 100}.

$$2x+y_{48}+\frac{615}{200}+\frac{10}{83}$$

Reduce the fraction \frac{615}{200} to lowest terms by extracting and canceling out 5.

$$2x+y_{48}+\frac{123}{40}+\frac{10}{83}$$

Least common multiple of 40 and 83 is 3320. Convert \frac{123}{40} and \frac{10}{83} to fractions with denominator 3320.

$$2x+y_{48}+\frac{10209}{3320}+\frac{400}{3320}$$

Since \frac{10209}{3320} and \frac{400}{3320} have the same denominator, add them by adding their numerators.

$$2x+y_{48}+\frac{10209+400}{3320}$$

Add 10209 and 400 to get 10609.

$$2x+y_{48}+\frac{10609}{3320}$$

Factor

$$\frac{6640x+3320y_{48}+10609}{3320}$$

Solution Steps

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$factor(2x+y_{48}+5\times \frac{1}{2}\times 1,23+\frac{10}{83})$$

Multiply 5 and \frac{1}{2} to get \frac{5}{2}.

$$factor(2x+y_{48}+\frac{5}{2}\times 1,23+\frac{10}{83})$$

Convert decimal number 1,23 to fraction \frac{123}{100}.

$$factor(2x+y_{48}+\frac{5}{2}\times \frac{123}{100}+\frac{10}{83})$$

Multiply \frac{5}{2} times \frac{123}{100} by multiplying numerator times numerator and denominator times denominator.

$$factor(2x+y_{48}+\frac{5\times 123}{2\times 100}+\frac{10}{83})$$

Do the multiplications in the fraction \frac{5\times 123}{2\times 100}.

$$factor(2x+y_{48}+\frac{615}{200}+\frac{10}{83})$$

Reduce the fraction \frac{615}{200} to lowest terms by extracting and canceling out 5.

$$factor(2x+y_{48}+\frac{123}{40}+\frac{10}{83})$$

Least common multiple of 40 and 83 is 3320. Convert \frac{123}{40} and \frac{10}{83} to fractions with denominator 3320.

$$factor(2x+y_{48}+\frac{10209}{3320}+\frac{400}{3320})$$

Since \frac{10209}{3320} and \frac{400}{3320} have the same denominator, add them by adding their numerators.

$$factor(2x+y_{48}+\frac{10209+400}{3320})$$

Add 10209 and 400 to get 10609.

$$factor(2x+y_{48}+\frac{10609}{3320})$$

Factor out \frac{1}{3320}.

$$\frac{6640x+3320y_{48}+10609}{3320}$$