Solve 2x+y-z^2=8

$$2 x + y - z ^ { 2 } = 8$$

Solve for x

$$x=\frac{8+z^{2}-y}{2}$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$2x-z^{2}=8-y$$

Add z^{2} to both sides.

$$2x=8-y+z^{2}$$

The equation is in standard form.

$$2x=8+z^{2}-y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{8+z^{2}-y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{8+z^{2}-y}{2}$$

Divide 8-y+z^{2} by 2.

$$x=\frac{z^{2}}{2}-\frac{y}{2}+4$$

Solve for y

$$y=8+z^{2}-2x$$

Solution Steps

Subtract 2x from both sides.

$$y-z^{2}=8-2x$$

Add z^{2} to both sides.

$$y=8-2x+z^{2}$$