Solve 2x+y-3z-1=0

$$2 x + y - 3 z - 1 = 0$$

Solve for x

$$x=\frac{1+3z-y}{2}$$

Steps for Solving Linear Equation

Subtract y from both sides. Anything subtracted from zero gives its negation.

$$2x-3z-1=-y$$

Add 3z to both sides.

$$2x-1=-y+3z$$

Add 1 to both sides.

$$2x=-y+3z+1$$

The equation is in standard form.

$$2x=1+3z-y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{1+3z-y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{1+3z-y}{2}$$

Solve for y

$$y=1+3z-2x$$

Solution Steps

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$y-3z-1=-2x$$

Add 3z to both sides.

$$y-1=-2x+3z$$

Add 1 to both sides.

$$y=-2x+3z+1$$