Solve for q (complex solution)
\left\{\begin{matrix}q=\frac{r-2x}{y}\text{, }&y\neq 0\\q\in \mathrm{C}\text{, }&x=\frac{r}{2}\text{ and }y=0\end{matrix}\right.
Solve for q
\left\{\begin{matrix}q=\frac{r-2x}{y}\text{, }&y\neq 0\\q\in \mathrm{R}\text{, }&x=\frac{r}{2}\text{ and }y=0\end{matrix}\right.
Solve for r
r=2x+qy
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qy=r-2x
Subtract 2x from both sides.
yq=r-2x
The equation is in standard form.
\frac{yq}{y}=\frac{r-2x}{y}
Divide both sides by y.
q=\frac{r-2x}{y}
Dividing by y undoes the multiplication by y.
qy=r-2x
Subtract 2x from both sides.
yq=r-2x
The equation is in standard form.
\frac{yq}{y}=\frac{r-2x}{y}
Divide both sides by y.
q=\frac{r-2x}{y}
Dividing by y undoes the multiplication by y.
r=2x+qy
Swap sides so that all variable terms are on the left hand side.
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