Solve 2x+7-5x-12=-8y+3

$$2 x + 7 - 5 x - 12 = - 8 y + 3$$

Solve for x

$$x=\frac{8\left(y-1\right)}{3}$$

Steps for Solving Linear Equation

Combine 2x and -5x to get -3x.

$$-3x+7-12=-8y+3$$

Subtract 12 from 7 to get -5.

$$-3x-5=-8y+3$$

Add 5 to both sides.

$$-3x=-8y+3+5$$

Add 3 and 5 to get 8.

$$-3x=-8y+8$$

The equation is in standard form.

$$-3x=8-8y$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{8-8y}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{8-8y}{-3}$$

Divide -8y+8 by -3.

$$x=\frac{8y-8}{3}$$

Solve for y

$$y=\frac{3x}{8}+1$$

Steps for Solving Linear Equation

Combine 2x and -5x to get -3x.

$$-3x+7-12=-8y+3$$

Subtract 12 from 7 to get -5.

$$-3x-5=-8y+3$$

Swap sides so that all variable terms are on the left hand side.

$$-8y+3=-3x-5$$

Subtract 3 from both sides.

$$-8y=-3x-5-3$$

Subtract 3 from -5 to get -8.

$$-8y=-3x-8$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{-3x-8}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{-3x-8}{-8}$$

Divide -3x-8 by -8.

$$y=\frac{3x}{8}+1$$