Solve 2x+5y+28+7=20+x^3+y

$$2 x + 5 y + 28 + 7 = 20 + x ^ { 3 } + y$$

Solve for y

$$y=\frac{x^{3}-2x-15}{4}$$

Steps for Solving Linear Equation

Add 28 and 7 to get 35.

$$2x+5y+35=20+x^{3}+y$$

Subtract y from both sides.

$$2x+5y+35-y=20+x^{3}$$

Combine 5y and -y to get 4y.

$$2x+4y+35=20+x^{3}$$

Subtract 2x from both sides.

$$4y+35=20+x^{3}-2x$$

Subtract 35 from both sides.

$$4y=20+x^{3}-2x-35$$

Subtract 35 from 20 to get -15.

$$4y=-15+x^{3}-2x$$

The equation is in standard form.

$$4y=x^{3}-2x-15$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{x^{3}-2x-15}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{x^{3}-2x-15}{4}$$

Divide -15+x^{3}-2x by 4.

$$y=\frac{x^{3}}{4}-\frac{x}{2}-\frac{15}{4}$$