Solve for x
x=\frac{4y}{3}
Solve for y
y=\frac{3x}{4}
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6x+4y=12x-4y
Combine 2x and 4x to get 6x.
6x+4y-12x=-4y
Subtract 12x from both sides.
-6x+4y=-4y
Combine 6x and -12x to get -6x.
-6x=-4y-4y
Subtract 4y from both sides.
-6x=-8y
Combine -4y and -4y to get -8y.
\frac{-6x}{-6}=-\frac{8y}{-6}
Divide both sides by -6.
x=-\frac{8y}{-6}
Dividing by -6 undoes the multiplication by -6.
x=\frac{4y}{3}
Divide -8y by -6.
6x+4y=12x-4y
Combine 2x and 4x to get 6x.
6x+4y+4y=12x
Add 4y to both sides.
6x+8y=12x
Combine 4y and 4y to get 8y.
8y=12x-6x
Subtract 6x from both sides.
8y=6x
Combine 12x and -6x to get 6x.
\frac{8y}{8}=\frac{6x}{8}
Divide both sides by 8.
y=\frac{6x}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{3x}{4}
Divide 6x by 8.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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