Solve 2x+4-3x+5*19

$$2 x + 4 - 3 x + 5 \times 19$$

Evaluate

$$99-x$$

Solution Steps

Combine 2x and -3x to get -x.

$$-x+4+5\times 19$$

Multiply 5 and 19 to get 95.

$$-x+4+95$$

Add 4 and 95 to get 99.

$$-x+99$$

Differentiate w.r.t. x

$$-1$$

Steps Using Derivative Rule for Sum

Combine 2x and -3x to get -x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x+4+5\times 19)$$

Multiply 5 and 19 to get 95.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x+4+95)$$

Add 4 and 95 to get 99.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x+99)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-x^{1-1}$$

Subtract 1 from 1.

$$-x^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$