Solve for x
x=\frac{9-3y}{2}
Solve for y
y=-\frac{2x}{3}+3
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2x-9=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
2x=-3y+9
Add 9 to both sides.
2x=9-3y
The equation is in standard form.
\frac{2x}{2}=\frac{9-3y}{2}
Divide both sides by 2.
x=\frac{9-3y}{2}
Dividing by 2 undoes the multiplication by 2.
3y-9=-2x
Subtract 2x from both sides. Anything subtracted from zero gives its negation.
3y=-2x+9
Add 9 to both sides.
3y=9-2x
The equation is in standard form.
\frac{3y}{3}=\frac{9-2x}{3}
Divide both sides by 3.
y=\frac{9-2x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2x}{3}+3
Divide -2x+9 by 3.
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