Solve for x
x=-\frac{3y}{2}+z+7
Solve for y
y=\frac{2\left(7+z-x\right)}{3}
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2x-2z=14-3y
Subtract 3y from both sides.
2x=14-3y+2z
Add 2z to both sides.
2x=14+2z-3y
The equation is in standard form.
\frac{2x}{2}=\frac{14+2z-3y}{2}
Divide both sides by 2.
x=\frac{14+2z-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}+z+7
Divide 14-3y+2z by 2.
3y-2z=14-2x
Subtract 2x from both sides.
3y=14-2x+2z
Add 2z to both sides.
3y=14+2z-2x
The equation is in standard form.
\frac{3y}{3}=\frac{14+2z-2x}{3}
Divide both sides by 3.
y=\frac{14+2z-2x}{3}
Dividing by 3 undoes the multiplication by 3.
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