Solve for x
x=\frac{5z-3y^{2}}{2}
Solve for y
y=\frac{\sqrt{15z-6x}}{3}
y=-\frac{\sqrt{15z-6x}}{3}\text{, }x\leq \frac{5z}{2}
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2x=5z-3y^{2}
Subtract 3y^{2} from both sides.
\frac{2x}{2}=\frac{5z-3y^{2}}{2}
Divide both sides by 2.
x=\frac{5z-3y^{2}}{2}
Dividing by 2 undoes the multiplication by 2.
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