Solve 2x+3y=3/8

$$2 x + 3 y = \frac { 3 } { 8 }$$

Solve for x

$$x=-\frac{3y}{2}+\frac{3}{16}$$

Steps for Solving Linear Equation

Subtract 3y from both sides.

$$2x=\frac{3}{8}-3y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{3}{8}-3y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{3}{8}-3y}{2}$$

Divide \frac{3}{8}-3y by 2.

$$x=-\frac{3y}{2}+\frac{3}{16}$$

Solve for y

$$y=-\frac{2x}{3}+\frac{1}{8}$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$3y=\frac{3}{8}-2x$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{\frac{3}{8}-2x}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{\frac{3}{8}-2x}{3}$$

Divide \frac{3}{8}-2x by 3.

$$y=-\frac{2x}{3}+\frac{1}{8}$$