Solve for x
x=\frac{63-7z-3y}{2}
Solve for y
y=-\frac{2x}{3}-\frac{7z}{3}+21
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2x+7z=63-3y
Subtract 3y from both sides.
2x=63-3y-7z
Subtract 7z from both sides.
2x=63-7z-3y
The equation is in standard form.
\frac{2x}{2}=\frac{63-7z-3y}{2}
Divide both sides by 2.
x=\frac{63-7z-3y}{2}
Dividing by 2 undoes the multiplication by 2.
3y+7z=63-2x
Subtract 2x from both sides.
3y=63-2x-7z
Subtract 7z from both sides.
3y=63-7z-2x
The equation is in standard form.
\frac{3y}{3}=\frac{63-7z-2x}{3}
Divide both sides by 3.
y=\frac{63-7z-2x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{2x}{3}-\frac{7z}{3}+21
Divide 63-2x-7z by 3.
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