Solve for x
x=\frac{-3y-5z+\sqrt{3}}{2}
Solve for y
y=\frac{-2x-5z+\sqrt{3}}{3}
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2x+5z=\sqrt{3}-3y
Subtract 3y from both sides.
2x=\sqrt{3}-3y-5z
Subtract 5z from both sides.
2x=-3y-5z+\sqrt{3}
The equation is in standard form.
\frac{2x}{2}=\frac{-3y-5z+\sqrt{3}}{2}
Divide both sides by 2.
x=\frac{-3y-5z+\sqrt{3}}{2}
Dividing by 2 undoes the multiplication by 2.
3y+5z=\sqrt{3}-2x
Subtract 2x from both sides.
3y=\sqrt{3}-2x-5z
Subtract 5z from both sides.
3y=-2x-5z+\sqrt{3}
The equation is in standard form.
\frac{3y}{3}=\frac{-2x-5z+\sqrt{3}}{3}
Divide both sides by 3.
y=\frac{-2x-5z+\sqrt{3}}{3}
Dividing by 3 undoes the multiplication by 3.
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