Solve for n
n=\frac{7-2x}{3}
Solve for x
x=\frac{7-3n}{2}
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3n=7-2x
Subtract 2x from both sides.
\frac{3n}{3}=\frac{7-2x}{3}
Divide both sides by 3.
n=\frac{7-2x}{3}
Dividing by 3 undoes the multiplication by 3.
2x=7-3n
Subtract 3n from both sides.
\frac{2x}{2}=\frac{7-3n}{2}
Divide both sides by 2.
x=\frac{7-3n}{2}
Dividing by 2 undoes the multiplication by 2.
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Limits
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