Solve for x
x\geq \frac{1}{3}
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2x+3-8x\leq 1
Subtract 8x from both sides.
-6x+3\leq 1
Combine 2x and -8x to get -6x.
-6x\leq 1-3
Subtract 3 from both sides.
-6x\leq -2
Subtract 3 from 1 to get -2.
x\geq \frac{-2}{-6}
Divide both sides by -6. Since -6 is negative, the inequality direction is changed.
x\geq \frac{1}{3}
Reduce the fraction \frac{-2}{-6} to lowest terms by extracting and canceling out -2.
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