Solve 2x+2y+2z-2t=0

$$2 x + 2 y + 2 z - 2 t = 0$$

Solve for t

$$t=x+y+z$$

Steps for Solving Linear Equation

Subtract 2x from both sides. Anything subtracted from zero gives its negation.

$$2y+2z-2t=-2x$$

Subtract 2y from both sides.

$$2z-2t=-2x-2y$$

Subtract 2z from both sides.

$$-2t=-2x-2y-2z$$

Divide both sides by -2.

$$\frac{-2t}{-2}=\frac{-2x-2y-2z}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$t=\frac{-2x-2y-2z}{-2}$$

Divide -2x-2y-2z by -2.

$$t=x+y+z$$

Solve for x

$$x=-\left(y+z-t\right)$$

Steps for Solving Linear Equation

Subtract 2y from both sides. Anything subtracted from zero gives its negation.

$$2x+2z-2t=-2y$$

Subtract 2z from both sides.

$$2x-2t=-2y-2z$$

Add 2t to both sides.

$$2x=-2y-2z+2t$$

The equation is in standard form.

$$2x=2t-2z-2y$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{2t-2z-2y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{2t-2z-2y}{2}$$

Divide -2y-2z+2t by 2.

$$x=t-z-y$$