Solve for x
x=40
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2x+\frac{1}{3}\times 100+\frac{1}{3}\left(-1\right)x=100
Use the distributive property to multiply \frac{1}{3} by 100-x.
2x+\frac{100}{3}+\frac{1}{3}\left(-1\right)x=100
Multiply \frac{1}{3} and 100 to get \frac{100}{3}.
2x+\frac{100}{3}-\frac{1}{3}x=100
Multiply \frac{1}{3} and -1 to get -\frac{1}{3}.
\frac{5}{3}x+\frac{100}{3}=100
Combine 2x and -\frac{1}{3}x to get \frac{5}{3}x.
\frac{5}{3}x=100-\frac{100}{3}
Subtract \frac{100}{3} from both sides.
\frac{5}{3}x=\frac{300}{3}-\frac{100}{3}
Convert 100 to fraction \frac{300}{3}.
\frac{5}{3}x=\frac{300-100}{3}
Since \frac{300}{3} and \frac{100}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{5}{3}x=\frac{200}{3}
Subtract 100 from 300 to get 200.
x=\frac{200}{3}\times \frac{3}{5}
Multiply both sides by \frac{3}{5}, the reciprocal of \frac{5}{3}.
x=\frac{200\times 3}{3\times 5}
Multiply \frac{200}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{200}{5}
Cancel out 3 in both numerator and denominator.
x=40
Divide 200 by 5 to get 40.
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