Solve 2x+1/3=4/3x-1

$$2 x + \frac { 1 } { 3 } = \frac { 4 } { 3 } x - 1$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Subtract \frac{4}{3}x from both sides.

$$2x+\frac{1}{3}-\frac{4}{3}x=-1$$

Combine 2x and -\frac{4}{3}x to get \frac{2}{3}x.

$$\frac{2}{3}x+\frac{1}{3}=-1$$

Subtract \frac{1}{3} from both sides.

$$\frac{2}{3}x=-1-\frac{1}{3}$$

Convert -1 to fraction -\frac{3}{3}.

$$\frac{2}{3}x=-\frac{3}{3}-\frac{1}{3}$$

Since -\frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{3}x=\frac{-3-1}{3}$$

Subtract 1 from -3 to get -4.

$$\frac{2}{3}x=-\frac{4}{3}$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.

$$x=-\frac{4}{3}\times \frac{3}{2}$$

Multiply -\frac{4}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-4\times 3}{3\times 2}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$x=-2$$