Solve for k
k=\frac{3x}{4\pi }+\frac{1}{12}
Solve for x
x=\frac{\pi \left(12k-1\right)}{9}
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12x+\pi =12k\pi +3x
Multiply both sides of the equation by 6, the least common multiple of 6,2.
12k\pi +3x=12x+\pi
Swap sides so that all variable terms are on the left hand side.
12k\pi =12x+\pi -3x
Subtract 3x from both sides.
12k\pi =9x+\pi
Combine 12x and -3x to get 9x.
12\pi k=9x+\pi
The equation is in standard form.
\frac{12\pi k}{12\pi }=\frac{9x+\pi }{12\pi }
Divide both sides by 12\pi .
k=\frac{9x+\pi }{12\pi }
Dividing by 12\pi undoes the multiplication by 12\pi .
k=\frac{3x}{4\pi }+\frac{1}{12}
Divide 9x+\pi by 12\pi .
12x+\pi =12k\pi +3x
Multiply both sides of the equation by 6, the least common multiple of 6,2.
12x+\pi -3x=12k\pi
Subtract 3x from both sides.
9x+\pi =12k\pi
Combine 12x and -3x to get 9x.
9x=12k\pi -\pi
Subtract \pi from both sides.
9x=12\pi k-\pi
The equation is in standard form.
\frac{9x}{9}=\frac{\pi \left(12k-1\right)}{9}
Divide both sides by 9.
x=\frac{\pi \left(12k-1\right)}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{4\pi k}{3}-\frac{\pi }{9}
Divide \pi \left(-1+12k\right) by 9.
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