Factor
\left(2w+7\right)\left(w^{2}+3\right)
Evaluate
\left(2w+7\right)\left(w^{2}+3\right)
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w^{2}\left(2w+7\right)+3\left(2w+7\right)
Do the grouping 2w^{3}+7w^{2}+6w+21=\left(2w^{3}+7w^{2}\right)+\left(6w+21\right), and factor out w^{2} in the first and 3 in the second group.
\left(2w+7\right)\left(w^{2}+3\right)
Factor out common term 2w+7 by using distributive property. Polynomial w^{2}+3 is not factored since it does not have any rational roots.
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