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a+b=1 ab=2\left(-1275\right)=-2550
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 2w^{2}+aw+bw-1275. To find a and b, set up a system to be solved.
-1,2550 -2,1275 -3,850 -5,510 -6,425 -10,255 -15,170 -17,150 -25,102 -30,85 -34,75 -50,51
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -2550.
-1+2550=2549 -2+1275=1273 -3+850=847 -5+510=505 -6+425=419 -10+255=245 -15+170=155 -17+150=133 -25+102=77 -30+85=55 -34+75=41 -50+51=1
Calculate the sum for each pair.
a=-50 b=51
The solution is the pair that gives sum 1.
\left(2w^{2}-50w\right)+\left(51w-1275\right)
Rewrite 2w^{2}+w-1275 as \left(2w^{2}-50w\right)+\left(51w-1275\right).
2w\left(w-25\right)+51\left(w-25\right)
Factor out 2w in the first and 51 in the second group.
\left(w-25\right)\left(2w+51\right)
Factor out common term w-25 by using distributive property.
w=25 w=-\frac{51}{2}
To find equation solutions, solve w-25=0 and 2w+51=0.
2w^{2}+w-1275=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
w=\frac{-1±\sqrt{1^{2}-4\times 2\left(-1275\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 1 for b, and -1275 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
w=\frac{-1±\sqrt{1-4\times 2\left(-1275\right)}}{2\times 2}
Square 1.
w=\frac{-1±\sqrt{1-8\left(-1275\right)}}{2\times 2}
Multiply -4 times 2.
w=\frac{-1±\sqrt{1+10200}}{2\times 2}
Multiply -8 times -1275.
w=\frac{-1±\sqrt{10201}}{2\times 2}
Add 1 to 10200.
w=\frac{-1±101}{2\times 2}
Take the square root of 10201.
w=\frac{-1±101}{4}
Multiply 2 times 2.
w=\frac{100}{4}
Now solve the equation w=\frac{-1±101}{4} when ± is plus. Add -1 to 101.
w=25
Divide 100 by 4.
w=-\frac{102}{4}
Now solve the equation w=\frac{-1±101}{4} when ± is minus. Subtract 101 from -1.
w=-\frac{51}{2}
Reduce the fraction \frac{-102}{4} to lowest terms by extracting and canceling out 2.
w=25 w=-\frac{51}{2}
The equation is now solved.
2w^{2}+w-1275=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
2w^{2}+w-1275-\left(-1275\right)=-\left(-1275\right)
Add 1275 to both sides of the equation.
2w^{2}+w=-\left(-1275\right)
Subtracting -1275 from itself leaves 0.
2w^{2}+w=1275
Subtract -1275 from 0.
\frac{2w^{2}+w}{2}=\frac{1275}{2}
Divide both sides by 2.
w^{2}+\frac{1}{2}w=\frac{1275}{2}
Dividing by 2 undoes the multiplication by 2.
w^{2}+\frac{1}{2}w+\left(\frac{1}{4}\right)^{2}=\frac{1275}{2}+\left(\frac{1}{4}\right)^{2}
Divide \frac{1}{2}, the coefficient of the x term, by 2 to get \frac{1}{4}. Then add the square of \frac{1}{4} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
w^{2}+\frac{1}{2}w+\frac{1}{16}=\frac{1275}{2}+\frac{1}{16}
Square \frac{1}{4} by squaring both the numerator and the denominator of the fraction.
w^{2}+\frac{1}{2}w+\frac{1}{16}=\frac{10201}{16}
Add \frac{1275}{2} to \frac{1}{16} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(w+\frac{1}{4}\right)^{2}=\frac{10201}{16}
Factor w^{2}+\frac{1}{2}w+\frac{1}{16}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(w+\frac{1}{4}\right)^{2}}=\sqrt{\frac{10201}{16}}
Take the square root of both sides of the equation.
w+\frac{1}{4}=\frac{101}{4} w+\frac{1}{4}=-\frac{101}{4}
Simplify.
w=25 w=-\frac{51}{2}
Subtract \frac{1}{4} from both sides of the equation.
x ^ 2 +\frac{1}{2}x -\frac{1275}{2} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 2
r + s = -\frac{1}{2} rs = -\frac{1275}{2}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{1}{4} - u s = -\frac{1}{4} + u
Two numbers r and s sum up to -\frac{1}{2} exactly when the average of the two numbers is \frac{1}{2}*-\frac{1}{2} = -\frac{1}{4}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{1}{4} - u) (-\frac{1}{4} + u) = -\frac{1275}{2}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{1275}{2}
\frac{1}{16} - u^2 = -\frac{1275}{2}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{1275}{2}-\frac{1}{16} = -\frac{10201}{16}
Simplify the expression by subtracting \frac{1}{16} on both sides
u^2 = \frac{10201}{16} u = \pm\sqrt{\frac{10201}{16}} = \pm \frac{101}{4}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{1}{4} - \frac{101}{4} = -25.500 s = -\frac{1}{4} + \frac{101}{4} = 25
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.