Solve 2v^4x^2-32x^2

$$2 v ^ { 4 } x ^ { 2 } - 32 x ^ { 2 }$$

Factor

$$2\left(v-2\right)\left(v+2\right)x^{2}\left(v^{2}+4\right)$$

Solution Steps

Factor out 2.

$$2\left(v^{4}x^{2}-16x^{2}\right)$$

Consider v^{4}x^{2}-16x^{2}. Factor out x^{2}.

$$x^{2}\left(v^{4}-16\right)$$

Consider v^{4}-16. Rewrite v^{4}-16 as \left(v^{2}\right)^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(v^{2}-4\right)\left(v^{2}+4\right)$$

Consider v^{2}-4. Rewrite v^{2}-4 as v^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(v-2\right)\left(v+2\right)$$

Rewrite the complete factored expression. Polynomial v^{2}+4 is not factored since it does not have any rational roots.

$$2x^{2}\left(v-2\right)\left(v+2\right)\left(v^{2}+4\right)$$

Evaluate

$$2x^{2}\left(v^{4}-16\right)$$