Solve 2u-4v-3+x-4=y

$$2 u - 4 v - 3 + x - 4 = y$$

Solve for u

$$u=\frac{7+4v+y-x}{2}$$

Steps for Solving Linear Equation

Subtract 4 from -3 to get -7.

$$2u-4v-7+x=y$$

Add 4v to both sides.

$$2u-7+x=y+4v$$

Add 7 to both sides.

$$2u+x=y+4v+7$$

Subtract x from both sides.

$$2u=y+4v+7-x$$

The equation is in standard form.

$$2u=7+4v+y-x$$

Divide both sides by 2.

$$\frac{2u}{2}=\frac{7+4v+y-x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$u=\frac{7+4v+y-x}{2}$$

Divide y+4v+7-x by 2.

$$u=\frac{y}{2}-\frac{x}{2}+2v+\frac{7}{2}$$

Solve for v

$$v=\frac{x-y+2u-7}{4}$$

Steps for Solving Linear Equation

Subtract 4 from -3 to get -7.

$$2u-4v-7+x=y$$

Subtract 2u from both sides.

$$-4v-7+x=y-2u$$

Add 7 to both sides.

$$-4v+x=y-2u+7$$

Subtract x from both sides.

$$-4v=y-2u+7-x$$

The equation is in standard form.

$$-4v=7-2u+y-x$$

Divide both sides by -4.

$$\frac{-4v}{-4}=\frac{7-2u+y-x}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$v=\frac{7-2u+y-x}{-4}$$

Divide y-2u+7-x by -4.

$$v=\frac{u}{2}+\frac{x}{4}-\frac{y}{4}-\frac{7}{4}$$