Factor
\left(2u-1\right)\left(u^{2}+8\right)
Evaluate
\left(2u-1\right)\left(u^{2}+8\right)
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u^{2}\left(2u-1\right)+8\left(2u-1\right)
Do the grouping 2u^{3}-u^{2}+16u-8=\left(2u^{3}-u^{2}\right)+\left(16u-8\right), and factor out u^{2} in the first and 8 in the second group.
\left(2u-1\right)\left(u^{2}+8\right)
Factor out common term 2u-1 by using distributive property. Polynomial u^{2}+8 is not factored since it does not have any rational roots.
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