Solve 2t^3-6t+3t^3-6t*t^2)

$$2 t ^ { 3 } - 6 t + 3 t ^ { 3 } - 6 t \cdot t ^ { 2 } )$$

Evaluate

$$-t\left(t^{2}+6\right)$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2t^{3}-6t+3t^{3}-6t^{3}$$

Combine 2t^{3} and 3t^{3} to get 5t^{3}.

$$5t^{3}-6t-6t^{3}$$

Combine 5t^{3} and -6t^{3} to get -t^{3}.

$$-t^{3}-6t$$

Factor

$$-t\left(t^{2}+6\right)$$

Solution Steps

Factor out t. Polynomial -t^{2}-6 is not factored since it does not have any rational roots.

$$t\left(2t^{2}-6+3t^{2}-6t^{2}\right)$$