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t^{2}\left(2t+5\right)+3\left(2t+5\right)
Do the grouping 2t^{3}+5t^{2}+6t+15=\left(2t^{3}+5t^{2}\right)+\left(6t+15\right), and factor out t^{2} in the first and 3 in the second group.
\left(2t+5\right)\left(t^{2}+3\right)
Factor out common term 2t+5 by using distributive property. Polynomial t^{2}+3 is not factored since it does not have any rational roots.