Solve for t
t=18
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2t-\frac{3}{2}t=9
Subtract \frac{3}{2}t from both sides.
\frac{1}{2}t=9
Combine 2t and -\frac{3}{2}t to get \frac{1}{2}t.
t=9\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
t=18
Multiply 9 and 2 to get 18.
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